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What is the equation, in vertex form, of the quadratic function that has a vertex at V(5, −4) and passes through point P(−1, 5)? (4 points)

User Helb
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Answer: To write the quadratic function in vertex form, we use the general form:

f(x) = a(x - h)^2 + k

where (h, k) represents the vertex of the parabola.

Given that the vertex is V(5, -4), we have h = 5 and k = -4. So the equation in vertex form is:

f(x) = a(x - 5)^2 - 4

Now, we need to find the value of 'a' to complete the equation. For this, we can use the point P(-1, 5) that the function passes through.

Substitute the coordinates of point P(-1, 5) into the equation:

5 = a(-1 - 5)^2 - 4

Simplify:

5 = a(-6)^2 - 4

5 = 36a - 4

Now, isolate 'a':

36a = 5 + 4

36a = 9

a = 9 / 36

a = 1/4

So, the value of 'a' is 1/4.

Now, we can write the final equation in vertex form:

f(x) = (1/4)(x - 5)^2 - 4

User Patricknelson
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