Explanation:
The probability of selecting one red ball from the box is 3/10.
Since the ball is replaced, the probability of selecting another red ball is also 3/10.
Therefore, the probability of obtaining two red balls is (3/10) * (3/10) = 9/100 or 0.09.
The probability of obtaining two white balls or two black balls is calculated as follows:
The probability of selecting one white ball from the box is 5/10.
Since the ball is replaced, the probability of selecting another white ball is also 5/10.
Therefore, the probability of obtaining two white balls is (5/10) * (5/10) = 25/100 or 0.25.
Similarly, the probability of obtaining two black balls is also 0.25.
The probability of obtaining one black ball and one red ball is calculated as follows:
The probability of selecting one black ball from the box is 2/10.
The probability of selecting one red ball from the box is 3/10.
Since the ball is replaced, the probability of selecting another ball that’s either black or red is (2/10 + 3/10) = 5/10.
Therefore, the probability of obtaining one black ball and one red ball is (2/10) * (3/10) * (5/10) * 2 = 6/100 or 0.06.