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A plane flying with a constant speed of 240 km/h passes over a ground radar station at an altitude of 1 km and climbs at an angle of 30°. At what rate (in km/h) is the distance from the plane to the radar station increasing a minute later? (Round your answer to the nearest whole number.)

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Answer: To find the rate at which the distance from the plane to the radar station is increasing a minute later, we can use the concept of related rates and trigonometry.

Let:

D = distance from the plane to the radar station (the hypotenuse of the right triangle formed by the plane, the radar station, and the ground)

h = altitude of the plane above the radar station (1 km)

θ = angle of elevation (30°)

v = speed of the plane (240 km/h)

The rate at which the distance D is changing can be found using the following formula:

Rate of change of D = (Rate of change of h) / sin(θ)

First, let's find the rate of change of h (the altitude of the plane) a minute later. Since the plane is flying at a constant speed and climbs at an angle of 30°, the vertical component of its speed (rate of change of h) can be found using trigonometry:

Rate of change of h = v * sin(θ)

Rate of change of h = 240 km/h * sin(30°)

Rate of change of h ≈ 240 km/h * 0.5

Rate of change of h ≈ 120 km/h

Now, we can find the rate at which the distance D is changing:

Rate of change of D = (Rate of change of h) / sin(θ)

Rate of change of D ≈ 120 km/h / sin(30°)

Using the value of sin(30°) ≈ 0.5:

Rate of change of D ≈ 120 km/h / 0.5

Rate of change of D ≈ 240 km/h

So, the distance from the plane to the radar station is increasing at a rate of approximately 240 km/h a minute later.

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