Question

If AC measures 8 and BC measures 12, what is the

length of the radius of this circle?
a. 8
b. 12
c. 04√13
d. 02√26

Answer 1

`\boxed{4√(13)}`

Explanation:

We see that there is a right triangle ΔABC in the figure such that AC and BC are the legs, and the radius is the hypotenuse. Using the Pythagorean theorem (
`a^2+b^2=c^2`), we get that
`8^2+12^2=r^2`. Simplifying the left side and taking the square root, we find that the radius is
`\boxed{4√(13)}`, or C.