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Iii. Express each of the following in partial fractions

2x³-x²+x+5 x²+3x+2 a.
b. x²-x x²+x+1
x+6 x3 3x²-4x+12
d. -x+7 (x+2)(x-1)²​

User Diliana
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1 Answer

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Answer: To express each of the given rational expressions in partial fractions, we need to factor the denominators and then use the method of partial fractions decomposition. Let's go through each one:

a. (2x³ - x² + x + 5) / (x² + 3x + 2)

Step 1: Factor the denominator

x² + 3x + 2 = (x + 2)(x + 1)

Step 2: Express the given rational expression in partial fractions:

(2x³ - x² + x + 5) / (x² + 3x + 2) = A/(x + 2) + B/(x + 1)

Step 3: Find the values of A and B:

2x³ - x² + x + 5 = A(x + 1) + B(x + 2)

Now, equate the coefficients of x³, x², x, and the constant term on both sides:

Coefficient of x³: 0 = A

Coefficient of x²: 2 = -A + B

Coefficient of x: 1 = A + 2B

Constant term: 5 = B

Solving the system of equations, we get:

A = 0

B = 5

So, the partial fraction decomposition is:

(2x³ - x² + x + 5) / (x² + 3x + 2) = 0/(x + 2) + 5/(x + 1)

b. (x² - x) / (x² + x + 1)

Step 1: Factor the denominator

x² + x + 1 does not factor further.

Step 2: Express the given rational expression in partial fractions:

(x² - x) / (x² + x + 1) = A/(x² + x + 1) + Bx/(x² + x + 1)

Step 3: Find the values of A and B:

x² - x = A + Bx

Now, equate the coefficients of x² and x on both sides:

Coefficient of x²: 1 = A

Coefficient of x: -1 = B

So, the partial fraction decomposition is:

(x² - x) / (x² + x + 1) = 1/(x² + x + 1) - x/(x² + x + 1)

c. (x + 6) / (x³ + 3x² - 4x + 12)

Step 1: Factor the denominator

x³ + 3x² - 4x + 12 does not factor further.

Step 2: Express the given rational expression in partial fractions:

(x + 6) / (x³ + 3x² - 4x + 12) = A/(x³ + 3x² - 4x + 12)

Step 3: Find the value of A:

x + 6 = A(x³ + 3x² - 4x + 12)

Now, equate the coefficients of x³, x², x, and the constant term on both sides:

Coefficient of x³: 0 = A

Coefficient of x²: 1 = 3A

Coefficient of x: 1 = -4A

Constant term: 6 = 12A

Solving the system of equations, we get:

A = 1/2

So, the partial fraction decomposition is:

(x + 6) / (x³ + 3x² - 4x + 12) = 1/(2x³ + 3x² - 4x + 12)

d. (-x + 7) / ((x + 2)(x - 1)²)

Step 1: Factor the denominator

(x + 2)(x - 1)² does not factor further.

Step 2: Express the given rational expression in partial fractions:

(-x + 7) / ((x + 2)(x - 1)²) = A/(x + 2) + B/(x - 1) + C/(x - 1)²

Step 3: Find the values of A, B, and C:

-x + 7 = A(x - 1)² + B(x + 2)(x - 1) + C(x + 2)

Now, equate the coefficients of x², x, and the constant term on both sides:

Coefficient of x²: 0 = A + B

Coefficient of x: -1 = -2A + C

Constant term: 7 = A + 2B + 2C

Solving the system of equations, we get:

A = 1

B = -1

C = 0

So, the partial fraction decomposition is:

(-x + 7) / ((x + 2)(x - 1)²) = 1/(x + 2) - 1/(x - 1)

These are the partial fractions for each given rational expression.

User Jeroen Bouman
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