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Find the area of a regular pentagon with n sides, each of length 2a metres​

User Puran
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A=1/4√(5(5+2√5))a² is the formula for a pentagon according to g**gle (I'm sorry). Plug 2a into the equation as a, to get

1/4√(5(5+2√5))(2a)²

This gives an answer of the rather long

√(10√(5)+25)·a²

Sorry about that

User Mdh
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