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A theater has 40 seats in the first row and 2 more seats in each subsequent row. There are 82 seats in the last row. How many rows and seats are in the theatre? (Show the algebraic equation being used)

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Answer:

Hi,

Explanation:

Number of rows: (value of last row - value of first row ) / (distance between 2 rows) +1


(82-40)/(2) +1=(42)/(2) +1=21+1=22\\\\

Number of seats: \\

((first row + last row)/2 )* number of rows

=
(40+82)/(2) *22=61*22=1342

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