Answer: To calculate the number of moles of reagent in each case, we can use the formula:
moles = concentration (M) × volume (L)
Note that we need to ensure that the volume is in liters (L) before performing the calculations.
a.) 25.00 mL of 0.10 M acetic acid:
Volume = 25.00 mL = 25.00 mL × (1 L / 1000 mL) = 0.025 L
Concentration (M) = 0.10 M
Moles of acetic acid = 0.10 M × 0.025 L = 0.0025 moles
b.) 5.55 mL of 0.092 M NaOH:
Volume = 5.55 mL = 5.55 mL × (1 L / 1000 mL) = 0.00555 L
Concentration (M) = 0.092 M
Moles of NaOH = 0.092 M × 0.00555 L = 0.0005116 moles
c.) 0.50 mL of 0.087 M HCl:
Volume = 0.50 mL = 0.50 mL × (1 L / 1000 mL) = 0.00050 L
Concentration (M) = 0.087 M
Moles of HCl = 0.087 M × 0.00050 L = 0.0000435 moles
So, the number of moles of reagent in each case is:
a.) 0.0025 moles of acetic acid
b.) 0.0005116 moles of NaOH
c.) 0.0000435 moles of HCl