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How many moles of reagent are in

a.) 25.00 mL of 0.10 M acetic acid
b.) 5.55mL of 0.092 M NaOH
c.) 0.50 mL of .087M HCl

1 Answer

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Answer: To calculate the number of moles of reagent in each case, we can use the formula:

moles = concentration (M) × volume (L)

Note that we need to ensure that the volume is in liters (L) before performing the calculations.

a.) 25.00 mL of 0.10 M acetic acid:

Volume = 25.00 mL = 25.00 mL × (1 L / 1000 mL) = 0.025 L

Concentration (M) = 0.10 M

Moles of acetic acid = 0.10 M × 0.025 L = 0.0025 moles

b.) 5.55 mL of 0.092 M NaOH:

Volume = 5.55 mL = 5.55 mL × (1 L / 1000 mL) = 0.00555 L

Concentration (M) = 0.092 M

Moles of NaOH = 0.092 M × 0.00555 L = 0.0005116 moles

c.) 0.50 mL of 0.087 M HCl:

Volume = 0.50 mL = 0.50 mL × (1 L / 1000 mL) = 0.00050 L

Concentration (M) = 0.087 M

Moles of HCl = 0.087 M × 0.00050 L = 0.0000435 moles

So, the number of moles of reagent in each case is:

a.) 0.0025 moles of acetic acid

b.) 0.0005116 moles of NaOH

c.) 0.0000435 moles of HCl

User Quindraco
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