Answer:
The answer is that the concentration of H+ in pure water at 25°C is 1.0 x 10^-7 M, and the concentration of OH- is also 1.0 x 10^-7 M. This is based on the equation for the water ion product constant, Kw, which is 1.0 x 10^-14 at 25°C.
Step-by-step explanation:
The equation for pure water at 25°C is the water ion product constant, also known as the Kw. At 25°C (298.15 K), the Kw is 1.0 x 10^-14.
The equation for the water ion product constant, Kw, is:
Kw = [H+][OH-]
Where [H+] and [OH-] represent the concentrations of hydrogen ion (H+) and hydroxide ion (OH-) in moles per liter (M) in water, respectively.
At 25°C, the concentration of H+ and OH- in pure water are equal, so we can simplify the equation to:
Kw = [H+]^2
Taking the square root of both sides, we get:
[H+] = sqrt(Kw) = sqrt(1.0 x 10^-14) = 1.0 x 10^-7 M
Therefore, the concentration of H+ in pure water at 25°C is 1.0 x 10^-7 M, and the concentration of OH- is also 1.0 x 10^-7 M.