Question

A bullet leaves riffle with muzzle velocity of 1042m/s . While accelerating through the barrel of the rifle , the bullet moves a distance of 1680m . Determine the acceleration of bullet ( assume a uniform acceleration )

Answer 1

Step-by-step explanation:

We can use the kinematic equation to solve for the acceleration of the bullet:

v² = u² + 2as

Where:

v = final velocity (muzzle velocity) = 1042 m/s

u = initial velocity (0 m/s, since the bullet starts from rest)

a = acceleration (unknown)

s = distance traveled (1680 m)

Substituting the given values into the equation:

1042² = 0² + 2a(1680)

1085764 = 3360a

Dividing both sides of the equation by 3360:

a = 1085764 / 3360

a ≈ 323.44 m/s²

Therefore, the acceleration of the bullet is approximately 323.44 m/s².

Answer 2

349.81

Step-by-step explanation:

We can use the kinematic equation:

v^2 = u^2 + 2as

where:

v = final velocity (which is the muzzle velocity of the bullet, 1042 m/s)

u = initial velocity (which is 0 m/s)

a = acceleration of the bullet

s = distance traveled through the barrel (1680 m)

Rearranging the equation, we get:

a = (v^2 - u^2) / 2s

Substituting the given values, we get:

a = (1042^2 - 0^2) / (2 x 1680) = 349.81 m/s^2

Therefore, the acceleration of the bullet is 349.81 m/s^2.