Question

A 170V power source is connected in series with a 1Ω resistor and a 6Ω resistor. What is the power dissipated in the 6Ω resistor?

Answer 1

The power dissipated in the 6Ω resistor is approximately 4816.67 Watts.

Step-by-step explanation:

To calculate the power dissipated in the 6Ω resistor, we'll use the formula:

Power (P) = (Voltage)^2 / Resistance

First, let's find the equivalent resistance (R_eq) of the series circuit. In a series circuit, the resistances add up:

R_eq = 1Ω + 6Ω = 7Ω

Now, we can calculate the power dissipated in the 6Ω resistor:

Power (P) = (Voltage)^2 / Resistance

P = (170V)^2 / 6Ω

P = 28900V^2 / 6Ω

P = 4816.67W

So, the power dissipated in the 6Ω resistor is approximately 4816.67 Watts.