Question

b. Determine the p.d. (voltage) which must be applied to a 2k2 resistor in order that a current of 10mA may flow.​

Answer 1

A voltage of 22 volts must be applied to the 2k2 resistor to allow a current of 10mA to flow through it.

Step-by-step explanation:

To determine the voltage (p.d. - potential difference) required to make a current of 10mA flow through a 2k2 resistor (2.2kΩ), you can use Ohm's Law. Ohm's Law states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by the resistance (R).

The formula for Ohm's Law is:

V = I * R

where:

V = Voltage (in volts)

I = Current (in amperes or amps)

R = Resistance (in ohms)

In this case, the current (I) is 10mA, which is equivalent to 0.01 amperes (A), and the resistance (R) is 2.2kΩ, which is equivalent to 2200 ohms.

Now, plug the values into the formula:

V = 0.01 A * 2200 Ω

V = 22 volts

So, a voltage of 22 volts must be applied to the 2k2 resistor to allow a current of 10mA to flow through it.