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Given g(x) = 8x2 − x + 3, find the following.g(0)

2 Answers

1 vote

EVALUATING FUNCTIONS


\mathbb{ANSWER:}

To find g(0), set x to 0 and evaluate it.


\sf \rightarrow g(x)=8x^2 - x + 3


\sf \rightarrow g(0)= \cancel{8(0)^2} - \cancel{(0)} + 3


\sf \rightarrow g(0) = 3

Hence, the answer is 3.

User BytesOfMetal
by
8.7k points
6 votes

Answer:

g(o) = 3

Explanation:

Substitute 0 for x

g(0) = (8)
0^(2) - 0 + 3

g(0) = 0 - 0 + 3

g(o) = 3

User Andrewvergel
by
7.8k points

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