Question

Given g(x) = 8x2 − x + 3, find the following.g(0)

Answer 1

EVALUATING FUNCTIONS

`\mathbb{ANSWER:}`

To find g(0), set x to 0 and evaluate it.

`\sf \rightarrow g(x)=8x^2 - x + 3`

`\sf \rightarrow g(0)= \cancel{8(0)^2} - \cancel{(0)} + 3`

`\sf \rightarrow g(0) = 3`

Hence, the answer is 3.

Answer 2

g(o) = 3

Explanation:

Substitute 0 for x

g(0) = (8)
`0^(2)` - 0 + 3

g(0) = 0 - 0 + 3

g(o) = 3