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Add. (6y3−4y2+7)+(3y3−y2−2y−5)
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Add. (6y3−4y2+7)+(3y3−y2−2y−5)

User Sujewan
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1 Answer

3 votes

Answer:


9y^3-5y^2-2y+2

Explanation:


(6y^3 - 4y^2+7) + (3y^3-y^2-2y−5) = 6y^3-4y^2+7+3y^3-y^2-2y-5


= 6y^3+3y^3-4y^2-y^2-2y+7-5\\= 9y^3-5y^2-2y+2

User Gavr
by
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