Answer:
Explanation:
For all of these parabolas, y = ax^2 + bx + c
the axis of symmetry will be x = 'the value of 'x' of the vertex'
the y value of the vertex will be found by using this value of x in the equation.
if 'a' is negative, it is a dome shaped parabola and will have a MAXIMUM at the vertex ......so examples 2,3,4 in your question will all have MAXIMA.
Here is the FIRST one ; x^2 - 10x + 2
a is positive (first term is + x^2)
this will be a bowl shaped parabola and it will have a MINIMUM at the vertex. the 'x' value is found by the equation
x = - b/2a and a +1 b = -10
x = - -10/ (2*1)= 5 this is the axis of symmetry AND the 'x' of the vertex find the 'y' value by putting x = -5 into the equation to find
y= (5)^2 -10(5) + 2 = -23 vertex (5, - 23)
THIRD one : -2x^2 - 8x + 5 maximum at x = - b/2a = - -8/(2*-2) = - 2
axis of symmetry x = -2
y of the vertex = -2(-2)^2 - 8 (-2) + 5 = 13
vertex = ( -2,13)
YOU try #2 and # 4