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Identify the equation of the circle that has its center at (-3, -4) and passes through the origin. A. (x−3)^2+(y−4)^2=25 B. (x−3)^2+(y−4)^2=5 C. (x+3)^2+(y+4)^2=5 D. (x+3)^2+(y+4)^2=25

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Answer:

D. (x+3)^2+(y+4)^2=25

Explanation:


(x-h)^2+(y-k)^2=r^2\\(x+3)^2+(y+4)^2=r^2\\\\(0+3)^2+(0+4)^2=r^2\\3^2+4^2=r^2\\9+16=r^2\\25=r^2\\\\(x+3)^2+(y+4)^2=25

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