Question

A population of a particular yeast cell develops with a constant relative growth rate of 0.4295 per hour. The initial population consists of 3.9 million cells. Find the population size (in millions of cells) after 5 hours. (Round your answer to one decimal place.)

Answer 1

`\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &3.9\\ r=rate\to 42.95\%\to (42.95)/(100)\dotfill &0.4295\\ t=hours\dotfill &5 \end{cases} \\\\\\ A = 3.9(1 + 0.4295)^(5) \implies A = 3.9( 1.4295 )^(5)\implies A \approx 23.3`