Answer:
the force applied to the smaller piston is 600 N
Step-by-step explanation:
Given;
weight of the car, F = 15,000 N
radius of the lager piston, R = 0.2 m
radius of the smaller piston, r = 0.04 m
let the force applied to the smaller piston = f
The pressure applied on both piston is constant;
Therefore, the force applied to the smaller piston is 600 N