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Solve for f(7)
f(x) = 2x² + 7x + 1​

User Lolski
by
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2 Answers

0 votes

Answer: f(7) = 148

Explanation:

In order to find f(7), substitute 7 for x:


\bullet\quad\sf{f(x)=2x^2+7x+1}


\bullet\quad\sf{f(7)=2(7)^2+7(7)+1}


\bullet\quad\sf{f(7)=2*49+49+1}


\bullet\quad\sf{f(7)=98+50}


\bullet\quad\sf{f(7)=148}

User Rodney Salcedo
by
8.0k points
4 votes

Final Answer:

  • f(7) = 148

In-depth explanation:

Hi! The question is asking us to solve for f(7).

Plug in 7 for x:


\sf{f(x)=2x^2+7x+1}

Note: Be sure to plug in 7 everywhere x occurs.


\sf{f(7)=2(7)^2+7(7)+1}


\sf{f(7)=2*49+49+1}

Remember PEMDAS.


\sf{f(7)=98+49+1}


\sf{f(7)=148}

Therefore, when x = 7, f(x) = 2x² + 7x + 1 equals 148.

User Neobot
by
8.1k points

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