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A body is displaced by 200m,when a force of 0.2N acts on the body. The work done is​

User Sukhmel
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Answer:

Without knowing the angle between the force and displacement vectors, we can't determine the exact work done.

Step-by-step explanation:

To calculate the work done on a body when a force acts on it and displaces it, you can use the formula:

Work (W) = Force (F) × Displacement (d) × cos(θ)

Where:

W = Work done (in joules)

F = Force applied (in newtons)

d = Displacement (in meters)

θ = Angle between the force vector and the displacement vector (cosine of the angle)

In this case, the force (F) is 0.2 N, and the displacement (d) is 200 meters. However, we don't have the angle (θ) between the force and displacement vectors, which means we can't calculate the work done without knowing the angle.

If the force is applied in the direction of the displacement (θ = 0 degrees), then the work done would be:

W = 0.2 N × 200 m × cos(0) = 0.2 N × 200 m × 1 = 40 joules

If the force is applied in the opposite direction of the displacement (θ = 180 degrees), then the work done would be:

W = 0.2 N × 200 m × cos(180) = 0.2 N × 200 m × (-1) = -40 joules

If the force is applied perpendicular to the direction of displacement (θ = 90 degrees), then the work done would be:

W = 0.2 N × 200 m × cos(90) = 0.2 N × 200 m × 0 = 0 joules

So, without knowing the angle between the force and displacement vectors, we can't determine the exact work done.

User Jorjj
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