Question

A random sample of 1999 adults was taken, and they were asked if they prefer watching sports, movies, or news on tv. They were also asked if they preferred dogs or cats.

Sports Movies News Total
Dogs 40 475 405 1281
Cats 160 335 223 718
Total 561 810 628 1999

a.
What is the probability that a person selected at random likes dogs and movies?

b. What is the probability that a person selected at random likes cats and news?

c. What is the probability that a person selected at random likes dogs or movies?

d. What is the probability that a person selected at random likes sports or cats?

Answer 1

a) 0.238 or 475/1999 (simplify the fractions if needed for all answers)

b) 0.168 or 335/1999

c) dogs: 0.640 or 1281/1999 movies: 0.405 or 810/1999 total: 1.005 or 2091/1999

d) cats: 0.359 or 718/1999 sports: 0.281 or 561/1999 total: 0.740 or 1279/1999

Explanation:

for the first two all you have to do if find where the two overlap on your table, and then divide it by the total number of people

for c and d, you should have to find the probabilities separately and then add them together, although I'm not 100% sure since c is over 100%. Please double check this, but I know a and b are correct.