Question

an aeroplane flying horizontally with a speed of 360kmph releases a bomb from height f 490m from the ground.When will the bomb reaches the ground

Answer 1

The time it takes for the bomb to hit the ground only depends on the vertical motion. We can use the equation of motion: h = 0.5gt^2, where h is the height, g is the acceleration due to gravity (approx. 9.8 m/s²), and t is the time.

Rearranging for t gives: t = sqrt(2h/g).

First, convert the height from meters to kilometers: 490m = 0.49km.

Then, plug in the values: t = sqrt(2*0.49km/9.8 m/s²) = sqrt(0.1 s²) = 0.316 s.

So, the bomb will hit the ground after approximately 0.316 seconds.