Sure, I can help you solve that equation. Here's the solution:
log_2(x^2 + 5x - 2) = log_2(x^2 + 3x - 6) + log_4(9)
Using the rule that log(a) + log(b) = log(ab), we can combine the two logarithms on the right-hand side of the equation to get:
log_2(x^2 + 5x - 2) = log_2((x^2 + 3x - 6) * 9)
Expanding the product on the right-hand side, we get:
log_2(x^2 + 5x - 2) = log_2(9x^2 + 27x - 54)
Equating the logarithms on both sides of the equation, we get:
x^2 + 5x - 2 = 9x^2 + 27x - 54
Solving for x, we get:
-8x = -56
x = 7
Therefore, the solution to the equation is x = 7.
Let me know if you have other math questions or requests.