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Log_2(X^2+5x-2)=log_2(x^2+3x-6)+log_4(9)​

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Sure, I can help you solve that equation. Here's the solution:

log_2(x^2 + 5x - 2) = log_2(x^2 + 3x - 6) + log_4(9)

Using the rule that log(a) + log(b) = log(ab), we can combine the two logarithms on the right-hand side of the equation to get:

log_2(x^2 + 5x - 2) = log_2((x^2 + 3x - 6) * 9)

Expanding the product on the right-hand side, we get:

log_2(x^2 + 5x - 2) = log_2(9x^2 + 27x - 54)

Equating the logarithms on both sides of the equation, we get:

x^2 + 5x - 2 = 9x^2 + 27x - 54

Solving for x, we get:

-8x = -56

x = 7

Therefore, the solution to the equation is x = 7.

Let me know if you have other math questions or requests.

User Jens Gustedt
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