136k views
4 votes
Tickets to a play cost $20 for adults and $5 for students .500 tickets were sold for $7000.how many adults and students attended ?

1 Answer

2 votes

Answer:

Let's assume the number of adult tickets sold is "a" and the number of student tickets sold is "s". From the information given, we know the following: 1. The cost of an adult ticket is $20, so the revenue from adult tickets sold is 20a. 2. The cost of a student ticket is $5, so the revenue from student tickets sold is 5s. 3. The total number of tickets sold is 500, so we have the equation: a + s = 500. 4. The total revenue from all tickets sold is $7000, so we have the equation: 20a + 5s = 7000. Now we can solve this system of equations using substitution or elimination. First, let's solve the equation a + s = 500 for a: a = 500 - s Substituting this value into the second equation, we have: 20(500 - s) + 5s = 7000 10000 - 20s + 5s = 7000 -15s = -3000 s = 200 Now, substitute the value of s into the first equation to find a: a + 200 = 500 a = 300 Therefore, 300 adults and 200 students attended the play.

Explanation:

User Anil Kocabiyik
by
8.5k points

No related questions found