Question

What volume (L) of 0.35 M HF contains 140 moles of HF

O 10L
20L
3.0L
04.0L
O 5.0L
06.0L

Answer 1

Solving for volume of solution:

Volume of solution = moles of solute / molarity

Volume of 0.35 M HF = 280 moles / 0.35 mol/L

Volume of 0.35 M HF = 800 L

Therefore, the volume of 0.35 M HF required to contain 140 moles of HE is 800 L. The closest option to this value is option D.