16.2k views
2 votes
The thermal energy needed to complete vapour is 36. 04 g of water at 100 Celsius is

1 Answer

3 votes

Answer: The thermal energy needed to completely vaporize 36.04 g of water at 100 degrees Celsius is approximately 1471.35 joules.

Step-by-step explanation:

To calculate the thermal energy required to complete vaporize 36.04 g of water at 100 degrees Celsius, we need to use the formula:

Q = m * ΔH_vap

where:

Q is the thermal energy (in joules) needed for vaporization,

m is the mass of the substance (in grams), and

ΔH_vap is the molar enthalpy of vaporization (in J/g) of the substance.

For water, the molar enthalpy of vaporization (ΔH_vap) is approximately 40.79 J/g at 100 degrees Celsius.

Now, plug in the values:

m = 36.04 g

ΔH_vap = 40.79 J/g

Q = 36.04 g * 40.79 J/g

Q ≈ 1471.3476 J

So, the thermal energy needed to completely vaporize 36.04 g of water at 100 degrees Celsius is approximately 1471.35 joules.

User Xikkub
by
8.6k points