Question

Suppose that the probability that Bob eats an apple at lunch is 8%. Also, suppose that the probability that Bob eats a pear at lunch is 13%. Also, suppose that the probability that Bob eats both an apple and a pear at

lunch is 2%. Find the probability that Bob will either eat an apple or a pear or both at lunch. Use rule based probability

Answer 1

The probability is 21%

Explanation:

P(Apple) = 8%

P(Pear) = 13%

P(Both Apple and Pear) = 2%

P(Either eat Apple or Pear or both) = P(Apple) + P(Pear) - P(Both Apple and Pear)

= (8% + 13% - 2% ) + 2%

= (8/100) + (13/100) - (2/100) +(2/100)

= 21%