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Partial sum of terms 12 to 15 of 88, 75, 62, 49….

User Ruleant
by
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1 Answer

3 votes

Answer:

-298.

Explanation:

This is an arithmetic sequence with first term a1 = 88 and common difference d = -13.

Sum on n terms = n/2 [2a1 + d(n - 1)]

---> sum of 15 terms = 15/2(2*88 - 13(15-1]

= 7.5 * -6

= -45

Sum of 11 terms = 11/2(2*88 - 13(11-1]

= 46*5.5

= 253

So partial sum of terms 12 to 15

= -45 - 253

= -298.

User Tcj
by
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