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An irreversible process takes place by which the entropy of the universe increases by 1.65 3/K. If the temperature of the environment in which the process occurred is 230 K, how much energy (in 3)

was made unavailable for useful work as a result?
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Answer:

379.5 joules (J) of energy were made unavailable for useful work as a result of this irreversible process.

Step-by-step explanation:

To calculate the amount of energy made unavailable for useful work during the irreversible process, we can use the formula:

ΔS_universe = ΔS_system + ΔS_environment

where:

ΔS_universe = Change in entropy of the universe

ΔS_system = Change in entropy of the system

ΔS_environment = Change in entropy of the environment

In this case, the change in entropy of the universe (ΔS_universe) is given as 1.65 J/K. The temperature of the environment (T_environment) is given as 230 K.

Since the process is irreversible, the change in entropy of the system (ΔS_system) will be zero, as the system is not in equilibrium with its surroundings during the process.

Now, we can calculate the change in entropy of the environment (ΔS_environment) using the formula:

ΔS_environment = ΔQ / T_environment

where:

ΔS_environment = Change in entropy of the environment

ΔQ = Heat exchanged with the environment

T_environment = Temperature of the environment

Since the change in entropy of the system is zero, all the energy absorbed as heat from the environment (ΔQ) is converted into an increase in entropy in the environment. So:

ΔS_environment = 1.65 J/K

ΔQ = ?

Now, rearrange the formula to solve for ΔQ:

ΔQ = ΔS_environment * T_environment

ΔQ = 1.65 J/K * 230 K

ΔQ = 379.5 J

Therefore, 379.5 joules (J) of energy were made unavailable for useful work as a result of this irreversible process.

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