Answer:
To calculate the molarity of sodium carbonate solution, we need to know the number of moles of sodium carbonate and the volume of the solution in liters.
First, let's calculate the number of moles of sodium carbonate:
Molar mass of sodium carbonate (Na2CO3) = (2 * atomic mass of sodium) + atomic mass of carbon + (3 * atomic mass of oxygen)
= (2 * 23) + 12 + (3 * 16)
= 46 + 12 + 48
= 106 g/mol
Number of moles of sodium carbonate = mass of sodium carbonate / molar mass of sodium carbonate
= 0.53 g / 106 g/mol
= 0.005 moles
Next, let's convert the volume of the solution from milliliters (mL) to liters (L):
Volume of solution in liters = volume of solution in milliliters / 1000
= 200 mL / 1000
= 0.2 L
Finally, we can calculate the molarity of sodium carbonate solution using the formula:
Molarity (M) = number of moles / volume of solution in liters
= 0.005 moles / 0.2 L
= 0.025 M
Therefore, the molarity of the sodium carbonate solution is 0.025 M.