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JIf x+1/x=5, find the value of x²+1/x²​
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JIf x+1/x=5, find the value of x²+1/x²​

User Svein Bringsli
by
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1 Answer

3 votes


x^2+(1)/(x^2)=\left(x+(1)/(x)\right)^2-2

Therefore, if
x+(1)/(x)=5 then


x^2+(1)/(x^2)=5^2-2=25-2=23

User Magiraud
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8.1k points
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