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How many grams of CO2 can be produced by thermally decomposing 8.8 moles of zinc carbonate?
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How many grams of CO2 can be produced by thermally decomposing 8.8 moles of zinc carbonate?

User Jesse Pollak
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The equation for the reaction:

ZnCO3 → ZnO + CO2

1 mol of ZnCO3 produces 1 mol of CO2
8.8 mol of ZnCO3 produces 8.8 mol CO2

no of mol = mass/Mr
8.8 = mass / 44
mass = 387.2g
User Ghusse
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