Answer:
To determine which point is a solution to the linear inequality y<−12x+2y<−21x+2, we can check each point's coordinates one by one.
Let's test each point:
Explanation:
Point (2, 3):
Substitute x = 2 and y = 3 into the inequality:
3<−12(2)+23<−21(2)+2
3<−1+23<−1+2
3<13<1
Since 3<13<1 is not true, this point is not a solution to the inequality.
Point (2, 1):
Substitute x = 2 and y = 1 into the inequality:
1<−12(2)+21<−21(2)+2
1<−1+21<−1+2
1<11<1
Again, 1<11<1 is not true, so this point is also not a solution to the inequality.
Point (3, -2):
Substitute x = 3 and y = -2 into the inequality:
−2<−12(3)+2−2<−21(3)+2
−2<−32+2−2<−23+2
−2<−12−2<−21
This time, −2<−12−2<−21 is true, so this point is a solution to the inequality.
Point (-1, 3):
Substitute x = -1 and y = 3 into the inequality:
3<−12(−1)+23<−21(−1)+2
3<12+23<21+2
3<523<25
3<523<25 is true, so this point is also a solution to the inequality.
Therefore, the points that are solutions to the inequality are:
(3, -2) and (-1, 3)