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Equilibrium expression for p4(g) <---> 2P2(g)

2 Answers

6 votes

Answer:

The equilibrium expression for the reaction P4(g) <---> 2P2(g) is represented by the law of mass action as:

K = [P2]^2 / [P4]

Where K is the equilibrium constant, [P2] is the molar concentration of P2 at equilibrium, and [P4] is the molar concentration of P4 at equilibrium. The exponents correspond to the stoichiometric coefficients in the balanced chemical equation.

User Lutfullah Tomak
by
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1 vote

Answer:

The equilibrium constant Kc for the reaction P4(g)⇌2P2(g) is 1.4 at 400oC.

User Dappawit
by
7.7k points
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