Question

Find the zero of h(x)=x^2+6x-27

Answer 1

x = 3 and -9

Explanation:

`x^(2)` + 6x -27 = 0

You are looking for 2 numbers that add to 6 and multiply to -27. That would be 9 and -3

(x + 9)(x -3) = 0

x + 9 = 0

x = -9

x - 3 = 0

x = 3

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