Question

A firecracker breaks up into three pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/s. A second piece has a mass of 300 g and flies off along the y-axis with a speed of 45.0 m/s. (a) What is the magnitude of the momentum for the third piece

Answer 1

`|P_3|=21.242m/s`

Step-by-step explanation:

From the question we are told that:

Mass
`m=200g=0.2`

Speed
`v=82.0m/s`

Mass
`M_2=300g=0.3kg`

Speed
`V_2=45.0m/s`

Generally the equation for Magnitude of the Third piece is mathematically given by

`P_1+P_2+P_3=0`

`|P_3|=|P_1+P_2|`

Where

`P_1=m_1v_1`

`P_1=0.2*82`

`P_1=16.4kgm/s`

And

`P_2=0.3*45`

`P_2=13.5kgm/s`

Therefore

`|P_3|=√(16.4^2+13.5^2)`

`|P_3|=21.242m/s`