Question

A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.09 m above the bottom of the chute with an initial speed of 1.51 m/s. The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with a coefficient of kinetic friction of 0.237. How far from the bottom of the chute does the toy zebra come to rest? Assume =9.81 m/s2.

Answer 1

mass of the boy = m kg
staring height of the boy = D meters
initial velocity = V
coefficient of kinetic friction = u
total energy of the toy is
E total = K.E. +P.E. = 0.5mv^2 +mgD = m(0.5v^2+ gD)
The work done by friction force
W= uxF_normal distance
W= uxm×g×d
hence, the distanced covered by the zebra toy and since, the total energy is conserved
W= E total
uxmxgxd= m(0.5v^2+ gD)
d = 0.50?+gD
MXg
hence, the distance d from the bottom of the chute does the toy algebra comes to rest.
0.5124gD d=
MXg