Question

NH​3​ is normally encountered as a gas with a pungent odor. It is formed from hydrogen and nitrogen (equation given below). A chemist pours a mixture of nitrogen gas and hydrogen gas in a 1.0 litre reaction vessel in 1:3 ratio. The equilibrium constant for the reaction is 1.0 × 10–​ 4​, and the equilibrium value of [H​2(​ g)] is 0.12 mol/L. Calculate the equilibrium value of [NH​3]​ .

N​2(​ g) + 3 H​2(​ g)⇔2 NH​3(​ g)

Answer 1

NH3 is normally encountered as a gas with a pungent odor. It is formed from hydrogen and nitrogen (equation given below). A chemist pours a mixture of nitrogen gas and hydrogen gas in a 1.0 litre reaction vessel in 1:3 ratio. The equilibrium constant for the reaction is 1.0 104, and the equilibrium value of [H2(g)] is 0.12 mol/L. Calculate the equilibrium value of [NH3] N2(g) + 3 H2(g) → 2 NH3(g)