Question

What mass of bromine will be produced if a potassium bromide solution reacts with 60.0mL of a 1.30mol/L solution of acidified Naclo4?

Answer 1

To answer this question, we need to know the balanced chemical equation for the reaction. Potassium bromide (KBr) reacts with sodium perchlorate (NaClO4) in an acidified solution to produce bromine (Br2), but the exact products can vary depending on the specific conditions and the acid used.

If we assume the reaction is as follows:

2KBr + NaClO4 → Br2 + 2KCl + NaO4

Then we can calculate the mass of bromine produced as follows:

First, we need to find the number of moles of NaClO4 in the solution:

Moles of NaClO4 = volume (L) * concentration (mol/L)

= 0.060 L * 1.30 mol/L

= 0.078 mol

According to the balanced equation, one mole of NaClO4 produces half a mole of Br2. So, we have:

Moles of Br2 = 0.078 mol * 0.5

= 0.039 mol

Finally, we find the mass of bromine produced:

Mass of Br2 = moles * molar mass

= 0.039 mol * 159.8 g/mol (molar mass of Br2)

= 6.23 g

So, approximately 6.23 g of bromine will be produced. Please verify the balanced equation and the reaction conditions as the exact products can vary.