137k views
2 votes
A rectangular piece of glass is thrice as long as it is wide. If both sides are reduced by 2cm the area becomes 39cm squared. What is the area of the original dimension of the glass?

User SamiAzar
by
8.0k points

1 Answer

0 votes

Answer:

75 cm²

Explanation:

You want to know the area of a piece of glass 3 times as long as it is wide, if reducing each dimension by 2 cm makes it have an area of 39 cm².

Factors

Assuming the glass has integer dimensions, we note that 39 = 3 × 13, and that increasing these factors by 2 gives two factors that have a ratio of 3:

(3+2) : (13+2) = 5 : 15 = 1 : 3

The original glass was 15 cm long and 5 cm wide, so had an area of ...

A = LW

A = (15 cm)(5 cm) = 75 cm²

The area of the original glass was 75 cm².

__

Additional comment

We could write a quadratic equation to find the width of the original glass:

(w-2)(3w-2) = 39

3w² -8w +4 = 39 . . . . . eliminate parentheses

3w² -8w -35 = 0 . . . . . . put in standard form

There are several ways we could solve this. One way is to factor it.

We're looking for factors of 3·35 = 105 that differ by 8. They are 15 and 7, so the factorization of this is ...

(3w +7)(3w -15)/3 = 0

(3w +7)(w -5) = 0 ⇒ w = 5 . . . . . the glass was 5 cm by 15 cm

<95141404393>

User Gautam Kumar Samal
by
8.1k points