Question

A particle moves along the x axis. Its position as a Part A function of time is given by x=6. 8t+8. 5t2, where t is in beconds and x is in meters. What is the acceleration as a function of time? Express your answer using two significant figures

Answer 1

17 m/s^2

Step-by-step explanation:

To find the acceleration as a function of time, we need to take the second derivative of the position function with respect to time.

Given the position function x = 6.8t + 8.5t^2, we can differentiate it twice to find the acceleration.

First derivative:

dx/dt = 6.8 + 17t

Second derivative:

d^2x/dt^2 = 17

Therefore, the acceleration as a function of time is a = 17 m/s^2.