Question

. Drops of rain fall perpendicular to the roof of a parked car during a rainstorm. The drops strike the roof with a speed of 15 m/s, and the mass of rain per second striking the roof is 0.071 kg/s. (a) Assuming the drops come to rest after striking the roof, find the average force exerted by the rain on the roof.

Answer 1

the average force exerted by the rain on the roof is 1.065 N

Step-by-step explanation:

Given;

speed of the rainfall, v = 15 m/s

the mass of the rate of the rainfall, m' (m/t) = 0.071 kg

Let the average force exerted by the rain on the roof = F

The average force exerted by the rain on the roof is calculated by Newton's second law of motion;

`F = ma = m (v)/(t) = (m)/(t) * v \\\\Recall, \ m' = (m)/(t) \\\\F = m'* v\\\\F = 0.071 * 15\\\\F = 1.065 \ N`

Therefore, the average force exerted by the rain on the roof is 1.065 N