Question

An iron-cored coil of 10 turns has reluctance of 100 AT/Wb. The inductance of the coil is (a)5H (b)1H (c) 0. 1H (c)10H

Answer 1

Answer: C :- 1H

Step-by-step explanation:
we can use the formula for inductance (L) of an inductor with an iron core:

L = N^2/ R

wher
N = Number of turns (10 turns in this case)
R = Reluctance of the core (given as 100 AT/Wb)

Put the values and calculate the inductance (L):

L= 10^2/100
L= 100/100
= 1

So, the inductance of the coil is 1 Henry (1H).