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An iron-cored coil of 10 turns has reluctance of 100 AT/Wb. The inductance of the coil is (a)5H (b)1H (c) 0. 1H (c)10H

User Muuvmuuv
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1 Answer

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Answer: C :- 1H

Step-by-step explanation:
we can use the formula for inductance (L) of an inductor with an iron core:

L = N^2/ R

wher
N = Number of turns (10 turns in this case)
R = Reluctance of the core (given as 100 AT/Wb)

Put the values and calculate the inductance (L):

L= 10^2/100
L= 100/100
= 1

So, the inductance of the coil is 1 Henry (1H).
User Richard Linares
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