Answer:
H2: 74.2%
O2: 4.63%
C2H4: 21.2%
Step-by-step explanation:
mol of H2:
5÷2
=2.5mol
mol of O2
5÷32
=0.15625
=0.156(~3s.f.)mol
mol of C2H4
20÷28
=0.714285714......
=0.714(~3s.f.)mol
percentage of gas = (moles of gas / total moles) x 100%
H2:
(2.5÷3.37) x 100%
=74.18397626......
=74.2%(~3s.f.)
O2:
(0.156÷3.37) x 100%
=4.629080119......
=4.63%(~3s.f.)
C2H4:
(0.714÷3.37) x 100%
=21.18694362......
=21.2%(~3s.f.)