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The answers are NOT

H2=16.7%
O2=16.7%
C2H4= 66.7%
(I ALREADY GOT IT WRONG)
fwi that’s not me yelling I just want to make sure no one uses those answers

The answers are NOT H2=16.7% O2=16.7% C2H4= 66.7% (I ALREADY GOT IT WRONG) fwi that-example-1
User Claudiu
by
8.5k points

1 Answer

3 votes

Answer:

H2: 74.2%

O2: 4.63%

C2H4: 21.2%

Step-by-step explanation:

mol of H2:

5÷2

=2.5mol

mol of O2

5÷32

=0.15625

=0.156(~3s.f.)mol

mol of C2H4

20÷28

=0.714285714......

=0.714(~3s.f.)mol

percentage of gas = (moles of gas / total moles) x 100%

H2:

(2.5÷3.37) x 100%

=74.18397626......

=74.2%(~3s.f.)

O2:

(0.156÷3.37) x 100%

=4.629080119......

=4.63%(~3s.f.)

C2H4:

(0.714÷3.37) x 100%

=21.18694362......

=21.2%(~3s.f.)

User Andrew Ebling
by
9.8k points

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