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A local hamburger shop sold a combined total805 of hamburgers and cheeseburgers on Wednesday. There were55 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Wednesday?

User Yaacov
by
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2 Answers

3 votes

Answer:

375 hamburgers

Explanation:

Let c stand for cheeseburgers and h stand for hamburgers.

We can write a system of equations that looks like this:


805=c+h


h+55=c

Because we are given what c equals with an equation, we can plug in the values for c into the first equation:


805=c+h\\805=(h+55)+h

simplify


805=2h+55

continue to solve for h (hamburgers) by subtracting 55 from both sides


750=2h

divide both sides by 2


375=h

So, 375 hamburgers were sold on Wednesday.

Hope this helps! :)

User Steviesh
by
8.0k points
1 vote

Answer:

x = the number of burgers sold

x+55= the number of cheeseburgers sold

he sold 805 hamburgers+chessebruggers combined

x+x+55=805

2x= 805-55

2x=750

x= 375

he sold 375 hamburgers

User Destaq
by
8.1k points