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Given △BAD
AB = 20, ED = 24, CA = 3x, and BE = 16 Find x to the nearest hundredth.

Given △BAD AB = 20, ED = 24, CA = 3x, and BE = 16 Find x to the nearest hundredth-example-1

1 Answer

3 votes

Answer: x = 4

Explanation:

First, let's find the length of side AD. We will need this information for later. We can find this with the pythagorean theorem. We know that AB = 20 and BD = 40 since sides BE and ED add up to 40.

a^2 + b^2 = c^2

20^2 + b^2 = 40^2

b ≈ 34.64 (side AD)

Now, let's find side CE. Since CE and AD are parallel to each other, triangles BCE and BAD are similar triangles. Let's set up a proportion to solve for CE.

CE/AD = BE/BD. These sides are the same corresponding sides in each of the triangles.

CE/34.64 = 16/40

Now solve for CE.

CE = 13.856

Now let's solve for side BC using the pythagorean theorem again.

a^2 + b^2 = c^2

a^2 + 13.856^2 = 16^2

a ≈ 8 (side BC)

Now we have all the information we need to solve for x.

AC + BC = AB

3x + 8 = 20

3x = 12

x = 4

I know it can be hard to visualize everything at once, so I provided a picture of the triangle but labeled with its lengths.

Given △BAD AB = 20, ED = 24, CA = 3x, and BE = 16 Find x to the nearest hundredth-example-1
User Raymond Reddington
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