168k views
0 votes
How many moles are present in 45.5 g of N₂ and 45.5 g of F₂?

User Pbasdf
by
8.4k points

1 Answer

4 votes

Answer: So, there are approximately 1.626 moles of N₂ and 1.197 moles of F₂ in 45.5 g of each gas.

Step-by-step explanation:To find the number of moles in a given mass of a substance, you can use the formula:

moles = mass / molar mass

1. First, find the molar mass of N₂ (nitrogen gas) and F₂ (fluorine gas).

- The molar mass of N₂ is 14.01 g/mol (since nitrogen has an atomic mass of 14.01 g/mol and there are two nitrogen atoms in N₂).

- The molar mass of F₂ is 38.00 g/mol (since fluorine has an atomic mass of 19.00 g/mol and there are two fluorine atoms in F₂).

2. Now, calculate the number of moles for each gas:

- For N₂: moles = 45.5 g / 28.02 g/mol = 1.626 mol (rounded to three decimal places)

- For F₂: moles = 45.5 g / 38.00 g/mol = 1.197 mol (rounded to three decimal places)

User Daotoad
by
7.6k points

Related questions

1 answer
4 votes
73.3k views
1 answer
0 votes
6.7k views