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A ball starting from rest slides down an inclined plane of length 10 m with a speed of 10 ms What is the acceleration produced in the ball?

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* Let's break this down step-by-step:

* A ball starts from rest and slides down an inclined plane

* Length of inclined plane (s) = 10 m

* Final speed of ball (v) = 10 m/s

* Acceleration (a) is to be determined

* Using kinematic equations:

* v = u + at

* Where:

* u = initial velocity = 0 m/s (since starting from rest)

* t = time taken

* We don't know the time taken, but we can eliminate it:

* 10 m/s = 0 + a(t)

* 10 m/s = a(t)

* a = 10/t m/s2

* Since the ball covers 10 m distance when reaching 10 m/s speed, we can say:

* t = s/v

* t = 10/10 = 1 s

* Substituting this in the acceleration equation:

* a = 10/1 = 10 m/s2

Therefore, the acceleration produced in the ball is 10 m/s2.

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