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When 36x^7y^3/4x^2y^-4 is simplified, the result can be written in the form ax^b y^c, where a is the coefficient, b is the exponent on the variable x, and c is the exponent on the variable y. Find the values of a, b, and c

User Jusopi
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1 Answer

1 vote

Answer:

a = 9 , b = 5 , c = 7

Explanation:

using the rule of exponents


(a^(m) )/(a^(n) ) =
a^((m-n))

given


(36x^7y^3)/(4x^2y^-4)separate the product of the variables

=
(36)/(4) ×
(x^7)/(x^2) ×
(y^3)/(y^-4)use the above rule to simplify

= 9 ×
x^((7-2)) ×
y^((3-(-4)))

= 9 ×
x^(5) ×
y^(3+4))

= 9
x^(5)
y^(7)in the form a
x^(b)
y^(c)

with a = 9 , b = 5 , c = 7

User Barney Mattox
by
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