Answer:
3. From statement 2 or Definition of right-angled triangle
4. Reflexive property
5. RHS axiom
6. Being congruent angle or Property of congruent triangle
7. From statement 6 and property of bisector
Explanation:
Given:
DF ≅ EF, DF ⊥ AB; EF ⊥BC.
Prove:
BF bisects ∡ABC
Statements( Reason in bracket)
1. DF ≅ EF, DF ⊥ AB; EF ⊥BC (Given)
2. ∡BDF and ∡BEF are rt. ∡s (Definition of ⊥ lines)
3. ΔBDF and ΔBEFare rt. Δs. (From statement 2 or Definition of right angled triangle)
4. BF ≅ BF. (Reflexive property)
5. ∴ ΔBDF ≅ ΔBEF (RHS axiom)
6. ∡DBF ≅ ∡EBF. (Being congruent side of congruent triangle or Property of congruent triangle)
7. ∴ BF bisects ∡ABC (From statement 6 and property of bisector)
